传送门→ 这双周赛改成贪心赛算了，fo了。 A拥有糖果最多的孩子 贪心+暴力。两重循环外层枚举每一个小朋友，内层去找当前的最大糖果数量。如果当前小朋友的糖加上额外给的能大于等于这个最大值就push一个1进去，否则push一个0。 B改变一个整数能得到的最大差值 还是暴力。对每一个数位进行枚举。三层循环外层枚举a中层枚举……
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edisoncgh
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于「3年前」在「互换友链」中说:
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于「3年前」在「互换友链」中说:( ,,´･ω･)ﾉ"(´っω･｀｡)
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