传送门 之前忙着开学，有相当一段时间没有做题了，实在是罪过… 数组 t1寻找数组的中心索引 找到数组中的一个位置，这个位置之前的所有元素和等于这个位置之后的所有元素和。如果没有就返回-1。 感觉思路有点滑动窗口的味道。维护两个变量lsum与rsum，分别表示当前位置左边的元素和与右边的元素和，然后根据题意O……
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于「3年前」在「互换友链」中说:
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